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Consider the equation y=2x²+4x+26.

Part A. Find the value of the discriminant. Show your work.
Part B. Based on the value of the discriminant found in part A, how many real roots does y=2x³+4x+26 have?
Part C. Use the quadratic formula to find the values of x when y-o. Show each step.

1 Answer

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Answer:

A. 4^2 - 4(2)(26) = 16 - 208 = -192

B. This equation has no real roots.

C. (-4 + √-192)/(2×2) = (-4 + 8i√3)/4

= -1 + (2√3)i

User Elvedin Hamzagic
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