Question

What is the molarity of a solution that was prepared by dissolving 12.3 g of Na,o (molar

mass = 62.0 g/mol) in enough water to make 564 mL of solution?

I need the steps..

Answer 1

• 0.34 M

Step-by-step explanation :

Molarity: It is defined as number of moles of solute dissolved per litre of solution.

Molarity is represented by 'M'

Required Formula :

`{ \boxed{\sf M = \frac{Number \: of \: moles \: of \: solute}{Volume \: of \: {sol}^(n) (ml) } * 1000}}`

Here,

Number of moles = Given mass/molar mass

• Given mass = 12.3 g
• Molar mass = 62.0 g

Substituting the values,

`:\implies` No. of moles = 12.3/62

`:\implies` 0.198 mol

Now,

`:\implies` M = 0.198/564 × 1000

`:\implies` M = 198/564

`:\implies` M = 0.34 M

Therefore, Molarity of the solution is 0.34 M