The ages of three men are in the ratio 3 : 4 : 5. If the difference between the ages of the oldest and the youngest is 18 years, find the sum of the ages of the three man.

Question

asked Dec 27, 2024 207k views

1 Answer

Neil Cresswell · Answer 1 · 2025-01-01T13:04:22+0000

Answer :

Step-by-step Step-by-step explanation:

It's given that The ages of three men are in the ratio 3 : 4 : 5

Let's assume,

Also, the difference between the ages of the oldest and the youngest is 18 years.

Difference in their ages ,

$:\implies$ 5x - 3x = 18 years

$:\implies$ 2x = 18

$:\implies$ x = 18/2

$:\implies$ x = 9

Hence,

Age of first men = 3x

$:\implies$ 3 × 9

$:\implies$ 27 years

Age of second men = 4x

$:\implies$ 4 × 9

$:\implies$ 36 years.

Age of thrid men = 5x

$:\implies$ 5 × 9

$:\implies$ 45 years.

Now, Sum of the ages of three man

$:\implies$ 27 + 36 + 45

$:\implies$ 108 years.

Therefore, The sum of the ages of three man is 108 years.