Question

The ages of three men are in the ratio 3 : 4 : 5. If the difference between the ages of the oldest and the youngest is 18 years, find the sum of the ages of the three man.

Answer 1

• Sum of their ages = 108 years.

Step-by-step Step-by-step explanation:

It's given that The ages of three men are in the ratio 3 : 4 : 5

Let's assume,

• Age of first men = 3x
• Second men = 4x
• Third men = 5x

Also, the difference between the ages of the oldest and the youngest is 18 years.

• Age of youngest men = 3x
• Age of oldest men = 5x

Difference in their ages ,

`:\implies` 5x - 3x = 18 years

`:\implies` 2x = 18

`:\implies` x = 18/2

`:\implies` x = 9

Hence,

Age of first men = 3x

`:\implies` 3 × 9

`:\implies` 27 years

Age of second men = 4x

`:\implies` 4 × 9

`:\implies` 36 years.

Age of thrid men = 5x

`:\implies` 5 × 9

`:\implies` 45 years.

Now, Sum of the ages of three man

`:\implies` 27 + 36 + 45

`:\implies` 108 years.

Therefore, The sum of the ages of three man is 108 years.