1 Answer

Neil Cresswell · Answer 1 · 2025-01-01T13:04:22+0000

Answer :

Step-by-step Step-by-step explanation:

It's given that The ages of three men are in the ratio 3 : 4 : 5

Let's assume,

Also, the difference between the ages of the oldest and the youngest is 18 years.

Difference in their ages ,

$:\implies$ 5x - 3x = 18 years

$:\implies$ 2x = 18

$:\implies$ x = 18/2

$:\implies$ x = 9

Hence,

Age of first men = 3x

$:\implies$ 3 × 9

$:\implies$ 27 years

Age of second men = 4x

$:\implies$ 4 × 9

$:\implies$ 36 years.

Age of thrid men = 5x

$:\implies$ 5 × 9

$:\implies$ 45 years.

Now, Sum of the ages of three man

$:\implies$ 27 + 36 + 45

$:\implies$ 108 years.

Therefore, The sum of the ages of three man is 108 years.

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