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Y= 2x-1 is a tangent to y=x^2. Name the point of tangency,

User Drf
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2 Answers

6 votes

The point of tangency between the line y = 2x - 1 and the parabola y = x^2 is found by setting the two equations equal and solving for x. The solution is x = 1, and after substituting x back into the original equation, we find that the point of tangency is (1, 1).

To find the point of tangency between the line y = 2x - 1 and the parabola y = x^2, we should equate these two equations and solve for x, because at the point of tangency, both the y values and slopes of the line and the curve will be the same.

First, we set the two equations equal to each other to find the x coordinate of the tangency point:

2x - 1 = x^2

Rearrange the equation:

x^2 - 2x + 1 = 0

This is a quadratic equation that factors to:

(x - 1)(x - 1) = 0

Therefore, x = 1 is the solution. To find the y coordinate, we substitute x back into either original equation. Using the linear equation:

y = 2(1) - 1

y = 1

The point of tangency is (1, 1).

10 votes

Answer:

Point of tangency is
x=1 or
(1,1)

Explanation:

You don't really need to use Calculus here. You can just set each equation to each other and solve for x (the point of tangency):


x^2=2x-1


x^2-2x+1=0


(x-1)(x-1)=0


x=1

Therefore, the point of tangency is
x=1 or
(1,1)

User Aleksey Isachenkov
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