Answer is in the graph
Your vertex is (-6, 0)
Your two other points are are
(-7,-1) and (-5,-1)
Given y= - (x + 6)^2
If you multiply this out, you get
- (x^2 + 12x + 36)
Multiply by the -1
- x^2 -12x -36 is your equation
Find the vertex by finding the x using formula
- b/2a
12 / 2*-1
12/-2 = -6
x = -6
Substitute -6 into equation to find y
y = -1 (-6)^2 (-12 * -6) -36
y = -1 * 36 + 72 -36
y = -36 + 72 -36
y = 0
Your vertex = ( -6, 0 )
To find another point for your parabola, chose a number close to your original x and sub into the equation f(x) = - x^2 -12x -36
f (-5) = -1 (-5)^2 (-12 * -5) -36
f(-5) = -1 * 25 + 60 -36
f(-5) = -25 + 60 -36
f(-5) = -1
So ( -5, -1) is your other point. Then find your symmetry point on the other side of your axis of symmetry (-6, 0 vertex is your center)
Graph your parabola.