Answer:
The given equation is:
det [a 10 e b d 0] = [2 10 3 6 -1 0]
The determinant of a 3x3 matrix is calculated as follows:
|a b c|
|d e f| = a(ei - fh) - b(di - fg) + c(dh - eg)
Applying this formula to the given matrix, we get:
det [a 10 e b d 0] = a(d0 - b-1) - 10(ed - b0) + e(10*-1 - d*3)
= ab + 10b - 10ed - 3e
Substituting the given values, we get:
ab + 10b - 10ed - 3e = 2(6-0) - 10(3-(-1)) + 3(10-(-1))
ab + 10b - 10ed - 3e = 12 + 40 + 33
ab + 10b - 10ed - 3e = 85
We can simplify this equation by factoring out b and e:
b(a + 10) - e(10d + 3) = 85 - 10b
We can solve for a, d, and e by setting up a system of equations using the given values of the determinant:
ab + 10b - 10ed - 3e = 85
From this equation, we can solve for b:
b(a + 10) - e(10d + 3) = 85 - 10b
Substituting the value of b from the determinant equation, we get:
(a+10)(-1) - e(10d+3) = -8.5
Simplifying, we get:
-a - 10e - 3.3d = -8.5 ...(1)
Also, from the determinant equation, we have:
6a + 10d + 3e = 29
Solving for e in terms of a and d, we get:
e = (29 - 6a - 10d)/3 ...(2)
Substituting equation (2) into equation (1), we get:
-a - 10[(29 - 6a - 10d)/3] - 3.3d = -8.5
Simplifying and multiplying both sides by -3, we get:
3a + 20d - 29e = 25.5
Substituting equation (2) into this equation, we get:
3a + 20d - 29[(29 - 6a - 10d)/3] = 25.5
Simplifying, we get:
a + 6d - 29 = 1.5
a + 6d = 30.5
We have two equations in two variables:
-a - 10e - 3.3d = -8.5
a + 6d = 30.5
Solving for a and d using any method (substitution, elimination, etc.), we get:
a = 7
d = 4
Substituting these values into equation (2), we get:
e = (29 - 6a - 10d)/3 = (29 - 6(7) - 10(4))/3 = -3
Therefore, a = 7, d = 4, and e = -3.
Explanation: