Answer:
Let the three numbers be x, y, and z.
We are given that x + y = z + 4.
We are also given that x + y + z >= 20 and x + y + z <= 28.
Combining these two inequalities, we get:
z + 4 + z >= 20
2z >= 16
z >= 8
Since z is an integer, z can be 8, 9, 10, 11, 12, 13, 14, 15, 16, or 17.
For each value of z, we can find the corresponding values of x and y using the equation x + y = z + 4.
For example, if z = 8, then x + y = 12.
So, the three integral values satisfying the inequality are 8, 4, and 0.
Another example is z = 15.
In this case, x + y = 19.
So, the three integral values satisfying the inequality are 15, 2, and 2.
There are many other possible solutions.