Answer:
a. To compare the concentration of 80 g/litre NaOH solution and 3 M NaOH solution, we need to convert one of the concentrations to the other unit.
One mole of NaOH weighs 40 grams. So, to convert 80 g/litre NaOH to Molarity, we can divide 80 g/litre by 40 g/mol to get:
80 g/litre NaOH = 2 M NaOH
Therefore, 3 M NaOH has a higher concentration than 80 g/litre NaOH solution.
b. To compare the concentration of 5.3 g/litre Na2CO3 and N/10 Na2CO3 solution, we need to first understand what N/10 solution means.
N/10 Na2CO3 means that the solution contains 1/10th of the normal concentration of Na2CO3. The normal concentration of Na2CO3 is the molar concentration of Na2CO3 that corresponds to the formula weight of Na2CO3, which is 106 g/mol.
So, the normal concentration of Na2CO3 is 1 mol/L or 1 M Na2CO3.
Therefore, N/10 Na2CO3 solution has a concentration of 1/10 M Na2CO3.
Now, let's compare the two concentrations:
5.3 g/litre Na2CO3 = (5.3/106) M Na2CO3 = 0.05 M Na2CO3
Since 0.05 M Na2CO3 is greater than 1/10 M Na2CO3, the concentration of 5.3 g/litre Na2CO3 solution is higher than that of N/10 Na2CO3 solution.
Step-by-step explanation: