Question

Need help ASAP, find the vertices of:

(x-2)^2/16-(y-1)^2/4=1

show work pls!!

Answer 1

Explanation:

(x - 2)²/16 - (y - 1)²/4 = 1

(x - 2)² - 4(y - 1)² = 16

x² + 4 - 4x - 4(y² + 1 - 2y) = 16

x² + 4 - 4x - 4y² - 4 + 8y = 16

x² - 4x + 8y - 4y² = 16

x² - 4x = 16 , -4y² + 8y = 16

x(x - 4) = 16 , 4y(-y + 2) = 16

x = 16, x = 20, y = 4, y = -14