Answer:
Explanation:
Here A be n×n matrix with real enties
y= Ax=xA is vector space.
Let m be set of all n*n matrix with real enties then m is vector space over IR.
we show y is vector subspace of m.
Here
identity matrix
IA=AI
∴ I ∈ y
∴ y is non empty subset of m.
Also if
,
∈ y ⇒ A
=
A ,A
=
A
for
∈ IR arbitrary

Hence
∈ y ∀
∈ y
∴ y is subspace of m.
∴ y is vector space.