Question

2. A new alloy of steel is 525 g at 100°C. It is dropped into 375 grams of water at 25 °C. The final temperature changes to 55°C, what is the specific heat of steel?​

Answer 1

The specific heat of the steel can be calculated using the formula:

Q = mcΔT

where Q is the heat transferred, m is the mass of the steel, c is the specific heat of the steel, and ΔT is the change in temperature.

First, calculate the heat transferred from the steel to the water:

Qsteel = mcΔT = (525 g)(c)(100 °C - 55 °C) = 27675c J

Next, calculate the heat transferred from the water to the steel:

Qwater = mcΔT = (375 g)(4.184 J/g. °C)(55 °C - 25 °C) = 50202 J

Since the heat lost by the steel is equal to the heat gained by the water:

Qsteel = Qwater

27675c J = 50202 J

c = 1.81 J/g. °C

Therefore, the specific heat of the steel is 1.81 J/g. °C.

Step-by-step explanation: