Question

Need help with his page 20 points

Answer 1

m/2 -6= m/4+2 can be solved as follows:

Multiply both sides of the equation by the least common multiple of the denominators, which is 4:

4(m/2 - 6) = 4(m/4 + 2)

2m - 24 = m + 8

Subtract m from both sides:

m - 24 = 8

Add 24 to both sides:

m = 32

Therefore, the value of m is C) 32.

k/12 = 25/100 can be solved as follows:

Multiply both sides of the equation by 12:

k = 12 * (25/100)

k = 3

Therefore, the value of k is A) 3.

9/5 = 3x/100 can be solved as follows:

Multiply both sides of the equation by 100:

100 * (9/5) = 3x

Simplify:

180/5 = 3x

36 = 3x

Divide both sides by 3:

x = 12

Therefore, the value of x is not one of the options provided.

Explanation:

Answer 2

Question 18:-

`\sf \longrightarrow \: (m)/(2) - 6 = (m)/(4) + 2 \\`

`\sf \longrightarrow \: (m - 12)/(2) = (m + 8)/(4)\\`

`\sf \longrightarrow \: 4(m - 12) =2(m + 8)\\`

`\sf \longrightarrow \: 4m \: - 48 =2m + 16\\`

`\sf \longrightarrow \: 4m \: - 2m = 16 + 48\\`

`\sf \longrightarrow \:2m = 64\\`

`\sf \longrightarrow \:m = (64)/(2) \: \\`

`\sf \longrightarrow \:m = 32 \: \\`

`\qquad{ \underline{\overline{ \boxed{ \sf{ \: \: C) \: \: \: 32 \: \: \: \: \: \checkmark }}}}} \: \: \bigstar`

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Question 19:-

`\sf \leadsto \: (k)/(12) = (25)/(100) \\`

`\sf \leadsto \: 100(k)= 12(25) \\`

`\sf \leadsto \: 100 * k= 12 * 25 \\`

`\sf \leadsto \: 100 k= 300 \\`

`\sf \leadsto \: k= (300)/(100) \\`

`\sf \leadsto \: k= 3 \\`

`\qquad{ \underline{\overline{ \boxed{ \sf{ \: \: a) \: \: \: 3 \: \: \: \: \: \checkmark }}}}} \: \: \bigstar`

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Question 20:-

`\sf \longrightarrow \: (9)/(5) = (3x)/(100) \\`

`\sf \longrightarrow \: 100(9)= 5(3x) \\`

`\sf \longrightarrow \: 100 * 9= 5 * 3x \\`

`\sf \longrightarrow \: 900= 15x \\`

`\sf \longrightarrow \: x= (900)/(15) \\`

`\sf \longrightarrow \: k= 60 \\`

`\qquad{\underline{\overline {\boxed{ \sf{ \: \: a) \: \: \: 60 \: \: \: \: \: \checkmark }}}}} \: \: \bigstar`

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