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Help me with the question please. (10 points)

Help me with the question please. (10 points)-example-1
User Syntac
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a rhombus is a parallelogram with a pair of opposite equal acute angles, a pair of opposite equal obtuse angles, and four equal sides.

in other words, it is a parallelogram with 4 equal sides, including a square as a special case.

the diagonal intersection point is the midpoint of both diagonals.

the diagonals intersect each other at a right angle (90°).

and they split each vertex angle in half.

so, they split the whole rhombus into 4 equal right-angled triangles.

and remember, the sum of all angles in a triangle is always 180°.

an "obtuse" angle means an angle larger than 90°.

an "acute" angle means an angle smaller than 90°.

because of all that, in the triangle PKE the angle K must be greater than 45° (90/2 = 45), so that the rhombus angle K can be "obtuse", as it must be twice the triangle angle K.

the triangle angle E is 90°.

so, the 16° must be triangle angle P.

and the triangle angle K is then

triangle angle K = 180 - 90 - 16 = 74°.

so, rhombus angle K = rhombus angle N = 2×74 = 148°

and triangle PMN angle N = 74°.

triangle PMN angle M = triangle PMN angle P = 16°.

User Topanga
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