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At the park there is a pool shaped like a circle with diameter 22 yd. A ring-shaped path goes around the pool. Its

width is 5 yd. If one gallon of coating can cover 5yd many gallons of coating do we need? Note that coating comes only by the gallon so the number of gallons must be a whole number. (Use the value 3.14 for pi.)

User Divick
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Answer: To find the area of the ring-shaped path, we need to subtract the area of the inner circle (the pool) from the area of the outer circle. The radius of the pool is half the diameter, so it is 11 yards. The radius of the outer circle is the sum of the radius of the pool and the width of the path, so it is 11 + 5 = 16 yards.

The area of the pool is:

A_pool = pi * r^2 = pi * 11^2 ≈ 380.13 square yards

The area of the outer circle is:

A_outer = pi * R^2 = pi * 16^2 ≈ 804.25 square yards

The area of the ring-shaped path is:

A_path = A_outer - A_pool ≈ 804.25 - 380.13 ≈ 424.12 square yards

Since one gallon of coating can cover 5 square yards, we need:

Gallons = A_path / 5 ≈ 424.12 / 5 ≈ 84.82

Therefore, we need approximately 85 gallons of coating to cover the ring-shaped path.

Explanation:

User AmeyaB
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