Answer:
BaF₂ when it dissolves, dissociates as follows;
BaF₂ --> Ba²⁺ + 2F⁻Molar solubility is the number of moles that can be dissolved in 1 L of solution.
If molar solubility of BaF₂ is x, then molar solubility of Ba²⁺ is x and solubility of
F⁻ is 2x.ksp = [Ba²⁺][F⁻]²ksp = (x)(2x)²2.45 x 10⁻⁵ = 4x³x³ = 0.6125 x 10⁻⁵x = 0.0183 mol/L is molar solubility of BaF₂ -blahblahmali
Step-by-step explanation: