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PLEASE HELP NOW ITS DUE TONIGHT!!!!

A zip line is constructed across a valley, as shown in the diagram. What is the width w of the valley? Round your answer to the nearest tenth.

w ≈__ft

PLEASE HELP NOW ITS DUE TONIGHT!!!! A zip line is constructed across a valley, as-example-1

2 Answers

4 votes

Answer:

w = 92.5

Explanation:

You cannot use Law of Sine in this case.

Use Law of Cosine.

They gave you 2 side length and one angle.

plug in your values into the equation and solve for w.

Let just use u, v, & w: Let u be 25 and v be 84.


w^2 = u^2 + v^2 - 2*u*v*cos(W)


w^2 = 25^2 + 84^2 - 2*25*84*cos(102)°


w^2=625+7056-4200*cos(102)


w^2=7681-4200*(-0.2079116908)


w^2=7681+873.2291014


w^2=8554.229101


w=√(8554.229101)= 92.48907558

PLEASE HELP NOW ITS DUE TONIGHT!!!! A zip line is constructed across a valley, as-example-1
User TheMayer
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7.6k points
4 votes

Answer: 92.5

Explanation:

User Eric Bock
by
8.0k points