54.9k views
3 votes
A combined total of $33,000 is invested in two bonds that pay 5% and 6.5% simple interest. The annual interest is $2,010.00. How much is invested in each bond?

1 Answer

5 votes

Answer: $9,000 is invested in the 5% bond, and $24,000 is invested in the 6.5% bond.

Step-by-step explanation: x + y = 33,000 (the full sum contributed)

We too know that the yearly intrigued earned is $2,010.00, which is the whole of the intrigued earned from each bond. Utilizing the equation for basic intrigued:

intrigued = principal x rate x time

ready to calculate the intrigued earned from each bond:

0.05x (for the 5% bond)

0.065y (for the 6.5% bond)

So we have another condition:

0.05x + 0.065y = 2,010

Presently we have two conditions with two factors, which we are able illuminate utilizing substitution or end.

Let's utilize substitution:

x + y = 33,000 --> y = 33,000 - x

0.05x + 0.065y = 2,010 --> 0.05x + 0.065(33,000 - x) = 2,010

Streamlining:

0.05x + 2,145 - 0.065x = 2,010

-0.015x = -135

x = 9,000

So the sum contributed within the 5% bond is $9,000, and the sum contributed within the 6.5% bond is:

y = 33,000 - x = 33,000 - 9,000 = $24,000

User Erickreutz
by
8.0k points

No related questions found