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How to find x on a triangle with given sides

User Luffe
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To find the value of an angle (let's call it angle A) in a triangle when the three sides are known, you can use the Law of Cosines, which states that:

a^2 = b^2 + c^2 - 2bc cos(A)

where a, b, and c are the side lengths of the triangle, and A is the angle opposite side a.

To solve for angle A, you can rearrange the equation to get:

cos(A) = (b^2 + c^2 - a^2) / 2bc

Then, you can take the inverse cosine (cos^-1) of both sides to get:

A = cos^-1[(b^2 + c^2 - a^2) / 2bc]

Once you have found the value of angle A, you can use the fact that the sum of the angles in a triangle is always 180 degrees to find the values of the other angles.
User Saddam Pojee
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