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Write a cosine function that has an amplitude of 2, a midline of y=3 and a period of 2/7​

User Fmg
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1 Answer

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Answer:

f(x) = 2 cos[7π x] + 3

Explanation:

The general form of a cosine function with amplitude A, midline y=m, and period P is:

f(x) = A cos[(2π/P) x] + m

Using the given values, we can substitute A=2, m=3, and P=2/7​ to get:

f(x) = 2 cos[(2π/(2/7)) x] + 3

Simplifying the expression inside the cosine function:

f(x) = 2 cos[7π x] + 3

This is a cosine function with an amplitude of 2, a midline of y=3, and a period of 2/7.

User BTL
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