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A simple circuit contains a battery connected with wires to a small bulb that has a resistance of 150 ohms. If the power dissipated by the bulb is 0.4 W, what is the voltage of the battery?

Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.

1 Answer

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Answer: The answer is 7.75v

Explanation; As we know,

power dissipated= (voltage)^2/resistance

0.4w = v^2/150

v^2=0.4w*150ohm

v^2=60

v=7.75v

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