The value of KL for the similar triangle ∆JKL is derived to be equal to 10.92
How to evaluate the for the value of x for the triangle ∆JKL
The triangles XYZ and JKL are similar, this implies that the length XY of the smaller triangle is similar to the length JK of the larger triangle
similarly, YZ is similar to KL so;
8.7/12.18 = 7.8/KL
KL = (7.8 × 12.18)/8.7 {cross multiplication}
KL = 95.004/8.7
KL = 10.92
Therefore, the value of KL for the similar triangle ∆JKL is derived to be equal to 10.92.