Question

Solve the following for θ, in radians, where 0≤θ<2π.

−sin2(θ)−4sin(θ)+4=0
Select all that apply:

1.1
2.52
0.98
0.69
1.43
2.17

Answer 1

Answer:0.98

2.17 are correct

Explanation:

-u^2 - 4u + 4 = 0

Multiplying both sides by -1, we get:

u^2 + 4u - 4 = 0

Now we can use the quadratic formula to solve for u:

u = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 1, b = 4, and c = -4. Substituting these values, we get:

u = (-4 ± sqrt(4^2 - 4(1)(-4))) / 2(1)

u = (-4 ± sqrt(32)) / 2

u = (-4 ± 4sqrt(2)) / 2

u = -2 ± 2sqrt(2)

Therefore, either: