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Write the equation of a line that passes through the point (0, 3) and (-4, 11). *

1 Answer

8 votes

Answer:

y = -2x + 3.

Explanation:

The slope = (11-3)/(-4-0)

= 8/-4

= -2.

Using the point-slope form of a straight line:

y - y1 = m(x - x1)

Here m = -2 and (x1, y1) = (0,3). then

y - 3 = -2(x - 0)

y - 3 = -2x

y = -2x + 3.

User Sigurd Garshol
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