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In △ABC, we are told that a=17, ∡B=70∘, and ∡C=48∘. Solve for b and c.

In △ABC, we are told that a=17, ∡B=70∘, and ∡C=48∘. Solve for b and c.-example-1
In △ABC, we are told that a=17, ∡B=70∘, and ∡C=48∘. Solve for b and c.-example-1
In △ABC, we are told that a=17, ∡B=70∘, and ∡C=48∘. Solve for b and c.-example-2

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Answer: b=18.1 and c=14.3

Step-by-step explanation:o solve for the lengths of the sides b and c in triangle ABC, we can use the law of sines, which relates the lengths of the sides of a triangle to the sines of the angles opposite those sides. Specifically, the law of sines states that:

a/sin(A) = b/sin(B) = c/sin(C)

where A, B, and C are the angles of the triangle opposite sides a, b, and c, respectively.

Given that a = 17, B = 70°, and C = 48°, we can write:

b/sin(70°) = 17/sin(A)

c/sin(48°) = 17/sin(A)

To solve for b and c, we need to find sin(A). We can do this by using the fact that the angles of a triangle sum to 180°:

A + B + C = 180°

A = 180° - B - C

A = 180° - 70° - 48°

A = 62°

Now we can substitute sin(A) = sin(62°) into the equations above and solve for b and c:

User Andrew Beals
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