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A conical paper cup has a diameter of 3 inches and a height of 3 inches. A cylindrical paper cup has a radius of 1.5

inches and a height of 3 inches. Suppose both cups are filled with water. If 1 cubic inch of water weighs 0.6 ounce,
how much more does the water in the cylindrical cup weigh? Round to the nearest tenth.

User DZN
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1 Answer

3 votes

Answer:

8.5 ounces.

Explanation:

The volume of the conical cup is given by the formula V = (1/3)πr²h, where r is the radius and h is the height. Since the diameter of the cup is 3 inches, the radius is 1.5 inches. Thus, the volume of the conical cup is:

V = (1/3)π(1.5²)(3) = 7.07 cubic inches

The volume of the cylindrical cup is given by the formula V = πr²h. Since the radius is 1.5 inches and the height is 3 inches, the volume of the cylindrical cup is:

V = π(1.5²)(3) = 21.2 cubic inches

To find the weight of the water in each cup, we need to multiply the volume of each cup by the weight of 1 cubic inch of water:

Weight of water in conical cup = 7.07 × 0.6 = 4.24 ounces

Weight of water in cylindrical cup = 21.2 × 0.6 = 12.72 ounces

Therefore, the water in the cylindrical cup weighs 12.72 - 4.24 = 8.48 more ounces than the water in the conical cup. Rounded to the nearest tenth, this is 8.5 ounces.

User Konrad Dzwinel
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