Answer:olution:. Given data:. Answer:. sum_(n=4)^10 15(3/10)^(n-1)= sum_(n=4)^10 15(0.3)^(n-1) = 15 [(0.3)^3 + (0.3)^4 + (0.3)^5+ (0.3)^6 + (0.3)^7+ (0.3)^8 + ...
Doesn’t include: 0.58 b 1.92 c 6.42 d 9.43
Evaluate: summation from n equals 4 to 10 of 15 times 3 tenths to the n minus 1 power period Round to the nearest hundredth.
Step-by-step explanation:Example
Evaluate X
4
r=1
r
3
.
Solution
This is the sum of all the r
3
terms from r = 1 to r = 4. So we take each value of r, work out
r
3
in each case, and add the results. Therefore
X
4
r=1
r
3 = 13 + 23 + 33 + 43
= 1 + 8 + 27 + 64
= 100 .
Example
Evaluate X
5
n=2
n
2
.
Solution
In this example we have used the letter n to represent the variable in the sum, rather than r.
Any letter can be used, and we find the answer in the same way as before:
X
5
n=2
n
2 = 22 + 32 + 42 + 52
= 4 + 9 + 16 + 25
= 54 .
Example
Evaluate X
5
k=0
2
k
.