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Evaluate: summation from n equals 4 to 10 of 15 times 3 tenths to the n minus 1 power period Round to the nearest hundredth.

a
0.58

b
1.92

c
6.42

d
9.43

1 Answer

2 votes

Answer:olution:. Given data:. Answer:. sum_(n=4)^10 15(3/10)^(n-1)= sum_(n=4)^10 15(0.3)^(n-1) = 15 [(0.3)^3 + (0.3)^4 + (0.3)^5+ (0.3)^6 + (0.3)^7+ (0.3)^8 + ...

Doesn’t include: 0.58 ‎b ‎1.92 ‎c ‎6.42 ‎d ‎9.43

Evaluate: summation from n equals 4 to 10 of 15 times 3 tenths to the n minus 1 power period Round to the nearest hundredth.

Step-by-step explanation:Example

Evaluate X

4

r=1

r

3

.

Solution

This is the sum of all the r

3

terms from r = 1 to r = 4. So we take each value of r, work out

r

3

in each case, and add the results. Therefore

X

4

r=1

r

3 = 13 + 23 + 33 + 43

= 1 + 8 + 27 + 64

= 100 .

Example

Evaluate X

5

n=2

n

2

.

Solution

In this example we have used the letter n to represent the variable in the sum, rather than r.

Any letter can be used, and we find the answer in the same way as before:

X

5

n=2

n

2 = 22 + 32 + 42 + 52

= 4 + 9 + 16 + 25

= 54 .

Example

Evaluate X

5

k=0

2

k

.

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