Question

Tom Brady attempts to kick a field-goal bare-foot. He imparts a speed of 43 m/s to a football initially at rest.

If the football has a mass of 0.53 kg and the time of contact with the ball is 0.021 s, what is the magnitude of the force exerted by the ball on the Tom Brady’s foot?

Answer 1

Answer: To calculate the magnitude of the force exerted by the ball on Tom Brady's foot, we can use the impulse-momentum theorem:

impulse = force × time

The impulse is equal to the change in momentum of the ball, which can be calculated using the following formula:

impulse = m × Δv

where m is the mass of the ball and Δv is the change in velocity of the ball.

In this case, the initial velocity of the ball is 0 m/s, and the final velocity is 43 m/s. Therefore, the change in velocity is:

Δv = 43 m/s - 0 m/s = 43 m/s

Substituting the values into the equation for impulse, we get:

impulse = m × Δv

impulse = 0.53 kg × 43 m/s

impulse = 22.79 N·s

Now, we can use the impulse-momentum theorem to find the magnitude of the force exerted by the ball on Tom Brady's foot:

impulse = force × time

22.79 N·s = force × 0.021 s

force = 22.79 N·s / 0.021 s

force = 1085.71 N

Therefore, the magnitude of the force exerted by the ball on Tom Brady's foot is approximately 1085.71 N.

The answer is: 1085.71 N.