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What is the area of a regular polygon with perimeter
58 and apothem 10 ?

User Deftwun
by
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1 Answer

4 votes
Let the length of each side be 2a.
Then perimeter
= 2an where n is the number of sides in the polygon.
So 2an = 58 and an = 29.
The number of triangles which make up the area of polygon = n and the area of
Of each triangle = apothem * a = 10a.

So, area of polygon = 10an = 10*29
= 290.
User Evan Chu
by
7.4k points

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