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125-foot redwood tree is leaning 20° off vertical. How long will its shadow be when the angle the sunlight makes with the ground is 68°?

User Janith
by
7.4k points

1 Answer

1 vote

Answer:

To solve this problem, we can use trigonometry. Let's call the length of the shadow "s" and the height of the tree "h". Since the tree is leaning, we can't just use the height of the tree directly as one leg of a right triangle. Instead, let's draw a diagram of the situation and see if we can find a way to use trigonometry.

|\

| \

| \ h

|20\

| \

| \

________|____\

s

In this diagram, the angle between the ground and the sunlight is 68 degrees, and the angle between the tree and the ground is 70 degrees (since the tree is leaning 20 degrees off vertical). We can use the tangent function to relate these angles to the lengths of the sides of the triangle:

tan(68) = h / s

tan(70) = h / (s + 125)

We can solve for "h" in terms of "s" using the second equation:

h = (s + 125) * tan(70)

Then we can substitute this expression for "h" into the first equation and solve for "s":

tan(68) = [(s + 125) * tan(70)] / s

s * tan(68) = (s + 125) * tan(70)

s * tan(68) = s * tan(70) + 125 * tan(70)

s = 125 * tan(70) / [tan(68) - tan(70)]

s ≈ 318.8 ft

Therefore , the shadow will be approximately 318.8 feet long.

Explanation:

User James Vince
by
7.9k points
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