Answer:
To solve this problem, we can use the following formula:
Volume of a pyramid = (1/3) * base area * height
The first step is to calculate the height of the pyramid. Since each side wall makes an angle of 45° with the plane of the base, the height is equal to the length of the altitude of the rhombus. The altitude can be calculated using the Pythagorean theorem:
altitude = sqrt((diagonal/2)^2 - (side/2)^2)
= sqrt((5.4/2)^2 - (4.5/2)^2)
= 2.7 cm
The base area of the pyramid is equal to the area of the rhombus:
base area = (diagonal1 * diagonal2) / 2
= (4.5 * 4.5) / 2
= 10.125 cm^2
Now, we can calculate the volume of the pyramid:
Volume = (1/3) * base area * height
= (1/3) * 10.125 * 2.7
= 9.1125 cm^3
Therefore, the volume of the pyramid is 9.1125 cm^3.
To calculate the area of the pyramid, we need to find the area of each triangular face. Since the pyramid has four triangular faces, we can calculate the total area by multiplying the area of one face by 4. The area of one face can be calculated using the following formula:
area of a triangle = (1/2) * base * height
where base is equal to the length of one side of the rhombus, and height is equal to the height of the pyramid. Since the rhombus is a regular rhombus, all sides have the same length, which is equal to 4.5 cm. Thus, we have:
area of a triangle = (1/2) * 4.5 * 2.7
= 6.075 cm^2
Therefore, the total area of the pyramid is:
area = 4 * area of a triangle
= 4 * 6.075
= 24.3 cm^2
Hence, the area of the pyramid is 24.3 cm^2.