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A spinner is divided into 10 equally sized sectors. The sectors are numbered 1 to 10. A randomly selected point is chosen.

What is the probability that the randomly selected point lies in a sector that is a factor of 8?

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A spinner is divided into 10 equally sized sectors. The sectors are numbered 1 to-example-1
User Arul Suju
by
8.2k points

2 Answers

3 votes

Answer:

2/10 meaning 20%

Explanation:

User Pvg
by
8.5k points
5 votes

Answer:

0.4 or 40%

Explanation:

The sectors that are factors of 8 are 1, 2, 4, and 8 itself. Therefore, out of 10 equally sized sectors, 4 are factors of 8.

The probability of selecting a sector that is a factor of 8 is the ratio of the number of favorable outcomes to the total number of possible outcomes

So, the probability of selecting a sector that is a factor of 8 is:

4 (number of favorable outcomes) / 10 (total number of possible outcomes)

which simplifies to:

2/5 or 0.4

Therefore, the probability that the randomly selected point lies in a sector that is a factor of 8 is 0.4 or 40%.

User Decoy
by
8.2k points