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16. The height, h(t), of a projectile launched upward from an initial height of 80 feet off the ground is represented by the function h(t) = -16€ + 64t + 80 where t is the number of seconds that have passed since it was launched. What is the average rate of change from t= 1 to t = 2?16. The height, h(t), of a projectile launched upward from an initial height of 80 feet off the ground is represented by the function h(t) = -16 + 64t + 80 where t is the number of seconds that have passed since it was launched. What is the average rate of change from t = 1 to t = 2?

User Shiran
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Answer: b. Solve the equation by factoring. 0=-16+2 -8 +120. 16€²+8E-120=0. 8(2²+E-15)=0. 8(2+-5) (++3)=0. 2=-5=0 =+3=0. + 5 t=-3. 2,5 seconds.

Explanation:

User Timchang Wuyep
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