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CuCl2 + NaNO3 --> Cu(NO3)2 + NaCl

If 16.0 grams of copper (II) chloride react with 23.2 grams of sodium nitrate, What is the maximum amount of NaCl that can be produced? The actual yield of NaCl after the experiment was 11.3 grams. Determine the limiting reactant, excess reactant, and the percent yield of NaCl

User Rogue Lad
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1 Answer

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Answer:

limitting reactant = 7.79g

excess reactant = 16.517g

percentage yild =145.05%

Step-by-step explanation:

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CuCl2 + NaNO3 --> Cu(NO3)2 + NaCl If 16.0 grams of copper (II) chloride react with-example-1
User Aroldo
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