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If diameter EF bisects BC, what is the angle of intersection?

If diameter EF bisects BC, what is the angle of intersection?-example-1
User Will Munn
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Angle is 80 degrees bisect
User Samarth Hattangady
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Answer:

The angle of the intersection is 90 degrees

Explanation:

How I know this is because EF is the diameter, which means that arc EF is equal to 180 degrees. Because we know this that means when it is spilt into two parts, the arc and angle measure has to be 90 degrees.

Another way to do this is to remember that a circle is 360 degrees and the circle is split into 4 parts. So all you have to do is divide 360/4 to get 90. Your answer.

User ReallyMadeMeThink
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