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PLEASE HELP

find the value of n
√25x^n × √20 = 10x⁵√5x​

1 Answer

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We can simplify this equation by using the properties of exponents and radicals.

First, we can simplify the square roots:

√25x^n × √20 = √(25x^n * 20)

Next, we can simplify the right side of the equation:

10x⁵√5x = 10 * x^5 * √(5x)

Now we can set the two sides of the equation equal to each other:

√(25x^n * 20) = 10 * x^5 * √(5x)

We can simplify the square root on the left side by factoring out 5:

√(25 * 5 * x^n * 4) = 10 * x^5 * √(5x)

Simplifying further:

5 * √(5 * x^n * 4) = 10 * x^5 * √(5x)

Now we can simplify the square root on the left side:

5 * √(20x^n) = 10 * x^5 * √(5x)

We can simplify the coefficient on the left side:

√(20x^n) = 2 * x^5 * √(5x)

Now we can square both sides of the equation to eliminate the square root:

20x^n = 4x^10 * 5x

Simplifying:

20x^n = 20x^11

Dividing both sides by 20:

x^n = x^11

Now we can solve for n by using the property that x^a / x^b = x^(a-b):

n = 11 - 1

n = 10

Therefore, the value of n is 10.
User ThomasGth
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