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A spinner is divided into 10 equally sized sectors. The sectors are numbered 1 to 10. A randomly selected point is chosen.

What is the probability that the randomly selected point lies in a sector that is a factor of 3?

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2 Answers

0 votes

Answer:

20%

Explanation:

For this question, we must find the numbers from 1-10 that are factors of 3. A factor is a number that, when multiplied by a specific number, gives a specific whole. For instance, in 2*4=8, 2 and 4 would be factors. The number 3 only has two factors: one and itself. Since two of the ten numbers are factors of 3, that is a rate of 2/10, 0.2, or 20%.

User Marsolk
by
7.8k points
4 votes

Answer:

  • 0.2 or 20%

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There are two sectors that are factors of 3:

  • sector 1, sector 3

So out of the 10 sectors, there is a 2/10 probability that the randomly selected point lies in one of these three sectors.

Therefore, the probability is 0.2 or 20%.

User Demosthenex
by
7.9k points