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2. A gift is packed in a rectangular box (rectangular prism) of dimensions 15 in, 10 in, and 8 in and it needs to be wrapped with gift paper. How much gift paper is required to wrap the gift box?

length= 5 in , width= 4 in, height= 3 in

User Shalay
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2 Answers

2 votes
Answer:

=700 sq in
= 94 sq in

Explanation:

To find the amount of gift paper required to wrap the gift box, we need to find the total surface area of the rectangular prism. The total surface area is the sum of the areas of all six faces of the rectangular prism.

The formula for the surface area of a rectangular prism is:

Surface area = 2lw + 2lh + 2wh

where l, w, and h are the length, width, and height of the rectangular prism, respectively.

For the given rectangular prism with dimensions 15 in, 10 in, and 8 in, we have:

l = 15 in, w = 10 in, h = 8 in

Substituting these values into the formula, we get:

Surface area = 2(15)(10) + 2(15)(8) + 2(10)(8)
Surface area = 300 + 240 + 160
Surface area = 700

Therefore, the amount of gift paper required to wrap the gift box is 700 square inches.

For the second part of the question, we need to find the surface area of the rectangular prism with dimensions 5 in, 4 in, and 3 in. Using the same formula, we have:

l = 5 in, w = 4 in, h = 3 in

Surface area = 2(5)(4) + 2(5)(3) + 2(4)(3)
Surface area = 40 + 30 + 24
Surface area = 94

Therefore, the amount of gift paper required to wrap the second gift box is 94 square inches.
User Jason Dancks
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8.6k points
3 votes

length, l=16in

width, b=13in

thickness, t=3in

To Find:-

Area of wrapping paper required.

Explanation:-

Since, wrapping paper is to be wrapped over the whole rectangular box.Therefore, we have to calculate the total surface area of the rectangular box.

Therefore, 590 of paper is required to wrap the whole rectangular box.

User Cyker
by
8.6k points