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How many moles of aluminum will be used when reacted with 1.35 moles of oxygen based on this chemical reaction? __Al + ___ O2 → 2Al2O3

This is due by midnight.

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Answer:

The balanced chemical equation is: 4Al + 3O2 → 2Al2O3

From the equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to form 2 moles of aluminum oxide.

Therefore, to find out how many moles of aluminum will react with 1.35 moles of oxygen, we can set up a proportion:

4 moles Al / 3 moles O2 = x moles Al / 1.35 moles O2

Cross-multiplying, we get:

4 moles Al × 1.35 moles O2 = 3 moles O2 × x moles Al

5.4 = 3x

x = 5.4 / 3

x = 1.8 moles Al

Therefore, 1.8 moles of aluminum will be used when reacted with 1.35 moles of oxygen

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