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How many moles of aluminum will be used when reacted with 1.35 moles of oxygen based on this chemical reaction? __Al + ___ O2 → 2Al2O3

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Answer:1.8 mol of Al Is required

Explanation:

first u must write the right chemical equetion

4Al + 3O2 ------> 2Al2O3 then u will write the proportion

x 1.35 mol

4Al + 3O2--------------> 2Al2O3

4 mol 3 mol

X/4 =1.35/3

X = (1.35 × 4) /3

X = 1.8 mol will be produced .

User Anibal Itriago
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