Answer:1.8 mol of Al Is required
Explanation:
first u must write the right chemical equetion
4Al + 3O2 ------> 2Al2O3 then u will write the proportion
x 1.35 mol
4Al + 3O2--------------> 2Al2O3
4 mol 3 mol
X/4 =1.35/3
X = (1.35 × 4) /3
X = 1.8 mol will be produced .