Answer: Sure thing! The solubility product constant (Ksp) for BaSO4 at 298 K is 1.1 x 10^-10. To calculate the solubility (S) of BaSO4 in mol/L at 298 K, we can use the following expression:
Ksp = [Ba2+][SO42-]
where [Ba2+] is the molar concentration of Ba2+ ions and [SO42-] is the molar concentration of SO42- ions in solution. Since BaSO4 is a sparingly soluble salt, we can assume that the concentration of Ba2+ and SO42- ions in solution is equal to the solubility of BaSO4 (S). Therefore:
Ksp = S^2
S = sqrt(Ksp)
S = sqrt(1.1 x 10^-10) = 1.05 x 10^-5 mol/L
Therefore, the solubility of BaSO4 in mol/L at 298 K is 1.05 x 10^-5 mol/L.
Step-by-step explanation: