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Equation: 2 KCIO3 →

Molar
Masses:
122.55
g/mol
2 KCI
74.55
g/mol
+
30₂
32.00
g/mol
Stoichiometry Problem:
How many moles of O2 will be formed from 3.3 moles of KCIO3?
Question 1E:
Calculate the answer to the correct number of significant figures (ONLY
type a number)

Equation: 2 KCIO3 → Molar Masses: 122.55 g/mol 2 KCI 74.55 g/mol + 30₂ 32.00 g/mol-example-1
User Rohitvats
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1 Answer

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Answer: The balanced chemical equation for the decomposition of KCIO3 is:

2KCIO3(s) → 2KCl(s) + 3O2(g)

According to the equation, 2 moles of KCIO3 produce 3 moles of O2. Therefore, to find the number of moles of O2 produced from 3.3 moles of KCIO3, we can set up a proportion:

2 mol KCIO3 / 3 mol O2 = 3.3 mol KCIO3 / x mol O2

Solving for x, we get:

x = (3 mol O2 * 3.3 mol KCIO3) / 2 mol KCIO3 = 4.95 mol O2

Rounded to the correct number of significant figures, the answer is 5 mol O2.

Step-by-step explanation:

User Swyx
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