Answer: 344 yd²
Explanation:
You can find the Area of the full block and then subtract the portion on the top right thats cut out
A(full block)=LA+2B P= 9+9+16+16=50 h=10 B=(9)(16)
= Ph+2B P, perimeter of Base; h, height B, area of base
=(50)(10)+2(144)
=788 yd²
A(cut out) = LA +2B P=13+13+4+4=34 h=10 B=(13)(4)=52
=Ph +2B
=34(10)+2(52)
=444 yd²
Now subtract the 2 areas and that will give you your shape
A(shape)=A(full block)-A(cut out)
A(shape)= 788-444=344 yd²