Question

PH of 1.6, its [OH-] would be

[H3O+] of 2.3E-5, it pH would be

[H3O+] of 4.6E-8, its [OH-] would be

[OH-] of 3.2E-4, its pH would be

pOH of 2.6, its [OH-] would be

pOH of 4.3, its [H3O+] would be

pH of 12.8, its [H3O+] would be

Answer 1

Answer: - For a pH of 1.6, its [OH-] would be 6.31E-14.

- For an [H3O+] of 2.3E-5, its pH would be 4.64.

- For an [H3O+] of 4.6E-8, its [OH-] would be 2.17E-7.

- For an [OH-] of 3.2E-4, its pH would be 9.50.

- For a pOH of 2.6, its [OH-] would be 2.51E-3.

- For a pOH of 4.3, its [H3O+] would be 4.47E-10.

- For a pH of 12.8, its [H3O+] would be 1.58E-13.

Step-by-step explanation: