Question

A line has a slope of

2/7 and passes through the point (7,0). Write its equation in slope-intercept form.

Answer 1

Answer:
`y=(2)/(7)x-7`

Explanation:

m=slope=2/7

point(7,0)

put into point-slope formula

`(y-y_(1))=m(x-x_(1))` where
`(x_(1) ,y_(1)) =(0,7)`

`y-7=(2)/(7)(x-0)` now put into slope- intercept(y=mx+b) form by simplifying, 0 goes away, and add 7 to both sides

`y=(2)/(7)x-7` b is your y-intercept, where it hits y-axis

Answer 2

Answer: The slope-intercept form of the equation of a line is y = mx + b, where "m" is the slope and "b" is the y-intercept.

We know that the slope of the line is 2/7. We can also find the y-intercept by plugging in the coordinates of the given point (7,0) and solving for "b".

0 = (2/7) * 7 + b

0 = 2 + b

b = -2

So the equation of the line in slope-intercept form is:

y = (2/7)x - 2

Explanation: