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How many moles are in 1.25 x 1021 molecules of sucrose?

How many moles of aspartame are present in 197 g of aspartame, C14H18N2O5?

1 Answer

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2.08x10^-3 moles Sucrose

6.69x10^-1 moles Aspartame

Take 1.25x10^21 then divide by Avogadro's number (6.02x10^23) and you're left with 0.00208 moles Sucrose. Then use your significant figures (3 in this case) and put it into scientific notation. 2.08x10^-3 moles.

Take the 197g of Aspartame, then divide by the molar mass of it (294.34g), and you're left with 0.669 moles. Use significant figures (3 again) and put into scientific notation, and you're left with 6.69x10^-1 moles.

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