149k views
3 votes
A learner pulls a box with a force of 500 N over a distance of 20 m. The an angle of 30° with the horizontal. The total mass of the box is 350 kg while the coefficient of friction between the box and the ground is 0,24. Draw a FORCE DIAGRAM indicating all forces acting on the box ?​

1 Answer

4 votes

Answer:

I can describe the forces acting on the box based on the information provided.

The force diagram for the box being pulled by the learner would include the following forces:

The force applied by the learner: This is a horizontal force of 500 N, which is directed at an angle of 30° with the horizontal.

The weight of the box: This is a vertical force that is equal to the mass of the box multiplied by the acceleration due to gravity (9.8 m/s²). The weight of the box can be calculated as follows: Weight = mass x gravity = 350 kg x 9.8 m/s² = 3430 N.

The normal force: This is the force exerted by the ground on the box in a direction perpendicular to the surface of the ground. It is equal and opposite to the weight of the box, and acts vertically upward.

The force of friction: This is a horizontal force that opposes the motion of the box and is equal to the coefficient of friction multiplied by the normal force. It can be calculated as follows: Force of friction = coefficient of friction x normal force = 0.24 x 3430 N = 823.2 N.

These forces are illustrated in a force diagram as arrows pointing in the direction of the force with the length of the arrow indicating the magnitude of the force. The force diagram helps to visualize the different forces acting on the box and how they contribute to the overall motion of the box.

User Erik Engheim
by
8.0k points