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What is the pressure of a 50.0L tank that contains 4.04kg of oxygen at 23 degrees celcius

User Guglhupf
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1 Answer

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To find the pressure, we can use the Ideal Gas Law: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the mass of oxygen (4.04 kg) to moles. The molar mass of oxygen (O2) is 32.00 g/mol.

4.04 kg * 1000 g/kg = 4040 g

4040 g / 32.00 g/mol = 126.25 moles of oxygen

Next, convert the temperature from Celsius to Kelvin:

23°C + 273.15 = 296.15 K

Now we can plug in the values into the Ideal Gas Law equation:

P * 50.0 L = 126.25 mol * 0.0821 L * atm / (mol * K) * 296.15 K

P = (126.25 * 0.0821 * 296.15) / 50.0

P ≈ 62.43 atm

The pressure of the tank is approximately 62.43 atm.
User Guinn
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