Question

The sum of three numbers is 144. The first number is 6 less than the third. The second number is 4 times the third. What are the numbers?

Answer 1

19, 100, and 25

Explanation:

Let's call the first number "x", the second number "y", and the third number "z". We know that:

x + y + z = 144 (the sum of three numbers is 144)

We also know that:

x = z - 6 (the first number is 6 less than the third)

y = 4z (the second number is 4 times the third)

We can substitute the expressions for x and y into the first equation:

x + y + z = 144

(z - 6) + 4z + z = 144

Combining like terms, we get:

6z - 6 = 144

Adding 6 to both sides:

6z = 150

Dividing by 6:

z = 25

Now that we know z, we can use the other equations to find x and y:

x = z - 6 = 25 - 6 = 19

y = 4z = 4(25) = 100

So the three numbers are 19, 100, and 25.

Answer 2

• 19, 100 and 25.

Explanation:

Let first number be a

second number be b

Third number be c

As per the question The first number is 6 less than the third. The second number is 4 times the third.

First number, a = c - 6 ....(i)

second number, b = 4c ....(ii)

Also sum of the three numbers is 144.

a + b + c = 144

c - 6 + 4c + c = 144

c + 4c + c = 144 + 6

6c = 150

c = 150/6

c = 25

Put value of c in equation (i) & (ii)

in equation (i)

a = c - 6

a = 25 - 6

a = 19

in equation (ii)

b = 4c

b = 4 × 25

b = 100

Hence thee required numbers will be 19, 100 and 25.