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Find the line parallel to y = -2x - 5

that includes the point (-1, 3).
Enter the y value of the point.
(× –
Remember: y - y₁ = m(x - x₁)
y- [?] =

Find the line parallel to y = -2x - 5 that includes the point (-1, 3). Enter the y-example-1
User Jay Elston
by
8.3k points

2 Answers

5 votes

Im horrible at this stuff but I tried for you

Find the line parallel to y = -2x - 5 that includes the point (-1, 3). Enter the y-example-1
User Marquinio
by
8.3k points
0 votes
To find the line parallel to y = -2x - 5 that includes the point (-1, 3), we'll use the same slope (m = -2) since parallel lines have the same slope.

Using the point-slope form: y - y₁ = m(x - x₁)

Plug in the values: y - 3 = -2(x - (-1))

Simplify: y - 3 = -2(x + 1)

Now, we can find the y value of the point:

y - 3 = -2(-1 + 1)
y - 3 = 0
y = 3

So, the y value of the point is 3.
User Ekalchev
by
7.4k points
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