Question

A jogger runs at 9 m/s, and is trailed by a bumblebee moving at 5 m/s and emitting a frequency of 270 Hz. What frequency does the jogger hear if the speed of sound in air was 336 m/s?​

Answer 1

The frequency that the jogger hears is given by the formula:

f’ = f * (v + vj) / (v + vs)

where f is the frequency of the bumblebee’s buzz (270 Hz), v is the speed of sound in air (336 m/s), vj is the speed of the jogger (9 m/s), and vs is the speed of the bumblebee (5 m/s).

Substituting these values into the formula gives:

f’ = 270 * (336 + 9) / (336 + 5) = 276 Hz

Therefore, the jogger hears a frequency of 276 Hz

Step-by-step explanation: